# Write a balanced equation for the complete combustion of 2-methylbutane

## Balanced symbol equation

That means that the bigger the hydrocarbon, the more likely you are to get a yellow, smoky flame. And so now my carbons are balanced, two carbons, two carbons. Let's see, I have two times two, so this right over here is four oxygens, and then I have three water molecules, each of them have one oxygen atom, so three times one, so this is going to be three right over here. Well two times three-and-a-half is equal to seven. II and III only So I have my ethane, and I won't write actually what state it's in just to save some time, plus some molecular oxygen. State the products of the complete combustion of alkanes. Instead of having one molecule of carbon dioxide, I can have two molecules of carbon dioxide. Draw the structural formula for each of these compounds and identify the compound that can be formed directly from C 2H4. I and II only c. They differ in their degree of saturation They combust, they yield, so these are the reactants, the products are carbon dioxide gas and liquid water, and liquid water. We were balanced here but we didn't have whole number coefficients. Remember I have two here, I'm saying two times something is equal to seven. A termination step may be between two radicals or between a radical and an impurity or the walls of the reaction vessel.

Draw a structural isomer, other than pentene, and name the compound. Carbon dioxide and water So right now, right now on, I'll do this in a mauve color, right now on the left hand side I have two oxygens, but on the right hand side what do I have?

## Chemical equation balancer

Which substance s could be formed during the incomplete combustion of a hydrocarbon? On the right hand side we have two plus, three oxygens, so none of the elements here are balanced. Analytical chemists can detect amounts of amino acids as small as 2. C9H20 Carbon dioxide and water In giving the name of a hydrocarbon with several substituents, in what order do we list the substituents? What type of reaction does the equation below represent? Just for kicks. We had a two right over here, multiply that by two you get a four. This is because the bigger molecules don't vaporize so easily - the reaction is much better if the oxygen and the hydrocarbon are well mixed as gases.

Explain why monomers are often gases or volatile liquids, whereas polymers are solids. But like we did in the example of ethylene, whenever you see this where you have several somewhat complex molecules involved, it's good to save the element that is in a molecule by itself for last, because you can just tweak this to change the number of oxygens without it having any other side effects on the number of carbons or hydrogens.

Al2O3 l C. So over here I have six hydrogens on the left hand side, of the entire left hand side I only have six hydrogen atoms. C7H16 e. But like we've seen in previous videos, it is not standard to just leave a three-and-a-half here, it's kind of this weird notion of three-and-a-half molecules, we like to have whole numbers here. What can multiply by two to get to seven?

Which of the following formulas represent alkanes? How many molecules does this represent?

### Complete the reaction

Ethanoic acid from ethene 2 steps d. Al2O3 l C. Well we could just multiply everything by two, then this thing is going to become a seven, this thing is going to become a two, this is going to become a four, this is going to become a six, so let's just do that. Just for kicks. Here on the left hand side we have six hydrogens. Carbon monoxide e. So what I'm going to do is I'm going to first balance, like we've done before, the carbons and the hydrogens, which are going to have implications on the oxygens because if I change the number here, it's going to change the number of oxygens. For each of the following straight-chain alkanes draw the structural formula and give the condensed structural formula a. They combust, they yield, so these are the reactants, the products are carbon dioxide gas and liquid water, and liquid water. Reaction Pathways: Give reactants and conditions, if necessary, that could be used to make the following a. Carbon dioxide and water During homolytic fission the bond breaks symmetrically so that one electron forming the bond between two atoms becomes attached to one of the atoms and the other electron becomes attached to the other atom resulting in the formation of two radicals.
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